document.write( "Question 474398: Nasser rode his bicycle 66 miles in 4.5 hours. for the first 40 miles he averaged a certain rate, and then for the last 26 miles he reduced his rate by 3 miles per hour. find his rate for the last 26 miles. \n" ); document.write( "
Algebra.Com's Answer #325367 by mananth(16946)\"\" \"About 
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Speed first part x mph
\n" ); document.write( "speed second part 3 mph less
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\n" ); document.write( "First part 40 miles
\n" ); document.write( "Second part 26 miles
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\n" ); document.write( "speed in first part x mph
\n" ); document.write( "speed second part x -5 mph
\n" ); document.write( "Total rowing time 4.5 hours
\n" ); document.write( "Time first part 40/x
\n" ); document.write( "Time second part 26/(x-5)
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\n" ); document.write( "Time first part + time second part =4.5 hours
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\n" ); document.write( "40/x+26/(x-5)=4.5
\n" ); document.write( "LCD =x* (x-5)
\n" ); document.write( "multiply the equation by the LCD
\n" ); document.write( "we get
\n" ); document.write( "40*(x-5 )+26x=4.5
\n" ); document.write( "40x-200 +26x=4.5X^2-22.5x
\n" ); document.write( "66x-200 =4.5x^2+200
\n" ); document.write( "4.5X^2-88.5x+200=0
\n" ); document.write( "4.5x^2 -88.5x+ 200=0
\n" ); document.write( "/4.5
\n" ); document.write( "x^2 -19.67 x +44.44 = 0
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\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 1 b= -19.67 c= 44.44
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\n" ); document.write( "b^2-4ac= 386.78 - -177.78
\n" ); document.write( "b^2-4ac= 209
\n" ); document.write( "\"sqrt%28%09209%09%29\"= 14.46
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 19.67 + 14.46 )/ 2
\n" ); document.write( "x1= 17.06
\n" ); document.write( "x2=( 19.67 -14.46 ) / 2
\n" ); document.write( "x2= 2.6
\n" ); document.write( "Ignore x2 value not posssible
\n" ); document.write( "x = 17.06 mph\r
\n" ); document.write( "\n" ); document.write( "17.06-6 = 12.06 mph speed second part
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