document.write( "Question 474398: Nasser rode his bicycle 66 miles in 4.5 hours. for the first 40 miles he averaged a certain rate, and then for the last 26 miles he reduced his rate by 3 miles per hour. find his rate for the last 26 miles. \n" ); document.write( "
Algebra.Com's Answer #325367 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Speed first part x mph \n" ); document.write( "speed second part 3 mph less \n" ); document.write( " \n" ); document.write( "First part 40 miles \n" ); document.write( "Second part 26 miles \n" ); document.write( " \n" ); document.write( "speed in first part x mph \n" ); document.write( "speed second part x -5 mph \n" ); document.write( "Total rowing time 4.5 hours \n" ); document.write( "Time first part 40/x \n" ); document.write( "Time second part 26/(x-5) \n" ); document.write( " \n" ); document.write( "Time first part + time second part =4.5 hours \n" ); document.write( " \n" ); document.write( "40/x+26/(x-5)=4.5 \n" ); document.write( "LCD =x* (x-5) \n" ); document.write( "multiply the equation by the LCD \n" ); document.write( "we get \n" ); document.write( "40*(x-5 )+26x=4.5 \n" ); document.write( "40x-200 +26x=4.5X^2-22.5x \n" ); document.write( "66x-200 =4.5x^2+200 \n" ); document.write( "4.5X^2-88.5x+200=0 \n" ); document.write( "4.5x^2 -88.5x+ 200=0 \n" ); document.write( "/4.5 \n" ); document.write( "x^2 -19.67 x +44.44 = 0 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 1 b= -19.67 c= 44.44 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 386.78 - -177.78 \n" ); document.write( "b^2-4ac= 209 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 19.67 + 14.46 )/ 2 \n" ); document.write( "x1= 17.06 \n" ); document.write( "x2=( 19.67 -14.46 ) / 2 \n" ); document.write( "x2= 2.6 \n" ); document.write( "Ignore x2 value not posssible \n" ); document.write( "x = 17.06 mph\r \n" ); document.write( "\n" ); document.write( "17.06-6 = 12.06 mph speed second part \n" ); document.write( " \n" ); document.write( " |