document.write( "Question 474310: The perimeter of a rectangle is 50 ft. Describe the possible length of a side if the area of the rectangle is not to exceed 114 square feet.\r
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document.write( " L * W > 114
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document.write( " 2(L * W) = 50
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document.write( " L + W = 25
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document.write( " -W -W
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document.write( " L = 25 – W
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Algebra.Com's Answer #325308 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is 50 ft. Describe the possible length of a side if the area of the rectangle is not to exceed 114 square feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " L * W > 114 \n" ); document.write( " 2(L * W) = 50 \n" ); document.write( " L + W = 25 \n" ); document.write( " -W -W \n" ); document.write( " L = 25 – W \n" ); document.write( "----------------- \n" ); document.write( "It's L*W <= 114 for \"not to exceed\" \n" ); document.write( "Sub for L \n" ); document.write( "W*(25-W) <= 114 \n" ); document.write( "W^2 - 25W + 114 <=0 \n" ); document.write( "(W - 6)*(W - 19) <= 0 \n" ); document.write( "--> 6 or 19 \n" ); document.write( "W = 6, L = 19 or \n" ); document.write( "W = 19, L = 6 \n" ); document.write( "-------------- \n" ); document.write( "W <= 6 for area <= 114 \n" ); document.write( "If one side is <= 6, the area is <= 114. \n" ); document.write( " |