document.write( "Question 472432: 7^(2X+1)=(1)/(3^(2-X) \n" ); document.write( "
Algebra.Com's Answer #325254 by lwsshak3(11628)\"\" \"About 
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7^(2X+1)=(1)/(3^(2-X)
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\n" ); document.write( "7^(2x+1)(3^(2-x)=1
\n" ); document.write( "take log of both sides
\n" ); document.write( "(2x+1)log7+(2-x)log3=log1=0
\n" ); document.write( "2xlog7+log7+2log3-xlog3=0
\n" ); document.write( "x(2log7-2log3)=-log7-2log3
\n" ); document.write( "x=-(log7+2log3)/(2log7-2log3)
\n" ); document.write( "using calculator:
\n" ); document.write( "x=-1.4833
\n" ); document.write( "Check:
\n" ); document.write( "7^(2X+1)=(1)/(3^(2-X)
\n" ); document.write( "7^(2*-1.4833+1)=(1)/3^(2-(-1.4833))
\n" ); document.write( "7^(-1.9666)=(1)/3^(3.4833)
\n" ); document.write( ".0218=.0218 \n" ); document.write( "
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