document.write( "Question 474142: Hi. I need help figuring out the absolute value of 3-2x=the absoulute value of 2x+3. Thank you so much. \n" ); document.write( "

Algebra.Com's Answer #325200 by edjones(8007) $\"\"$ $\"About$

You can put this solution on YOUR website!
|3-2x|=|2x+3|
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\n" ); document.write( "3-2x=0
\n" ); document.write( "-2x=-3
\n" ); document.write( "x=3/2 inflection point after which 3-2x is less than 0 because it has a negative slope.
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\n" ); document.write( "2x+3=0
\n" ); document.write( "2x=-3
\n" ); document.write( "x=-3/2 infection point after which 2x+3 increases in value because the slope is positive.
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\n" ); document.write( "X(-infinity, -3/2)
\n" ); document.write( "-(2x+3)=(3-2x) [2x+3 is negative below x=-3/2]
\n" ); document.write( "-2x-3=3-2x
\n" ); document.write( "0=6 No answer
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\n" ); document.write( "X(-3/2, 3/2)
\n" ); document.write( "3-2x=2x+3 [both statements are positive between x=-3/2 and 3/2]
\n" ); document.write( "-4x=0
\n" ); document.write( "x=0
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\n" ); document.write( "X(3/2, infinity)
\n" ); document.write( "-(3-2x)=2x+3 [3-2x is negative above x=3/2]
\n" ); document.write( "2x-3=2x+3
\n" ); document.write( "0=6 no answer
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\n" ); document.write( "x=0 the only answer
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\n" ); document.write( "Ed
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\n" ); document.write( " $\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2Cabs%283-2x%29%2Cabs%282x%2B3%29%29\"$ \n" ); document.write( "

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