document.write( "Question 49056: I am not sure how to go about changing the following problem into standard form. I tried to do completing the square, but I'm not sure how to use it in this situation or when there is a coefficient other than 1 in front of x^2 and y^2. I would greatly appreciate help on how to solve the following problem. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Change the equation to standard form and name the figure.\r
\n" ); document.write( "\n" ); document.write( "3x^2-2y^2-12x-20y-44=0
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Algebra.Com's Answer #32519 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
\"3x%5E2+-+2y%5E2+-+12x+-+20y+-+44+=+0\"
\n" ); document.write( "\"3x%5E2+-+12x+-+2y%5E2+-+20y+=+44\"
\n" ); document.write( "\"3%28x%5E2+-+4x%29+-+2%28y%5E2+%2B+10y%29+=+44\"
\n" ); document.write( "\"3%28x%5E2+-+4x%29+-+2%28y%5E2+%2B+10y%29+=+44\"
\n" ); document.write( "\"3%28x+-+2%29%5E2+-+2%28y+%2B+5%29%5E2+=+44+%2B+4%2A3+%2B+25%2A2\" You square the number, then multiply it by the coefficient.
\n" ); document.write( "\"3%28x+-+2%29%5E2+-+2%28y+%2B+5%29%5E2+=+106\"
\n" ); document.write( "\"%28x+-+2%29%5E2%2F%28106%2F3%29+-+%28y+%2B+5%29%5E2%2F53+=+1\"
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