document.write( "Question 474076: 2 sqrt 5/7 - 3 sqrt 7/5 + sqrt 140 \n" ); document.write( "
Algebra.Com's Answer #325152 by edjones(8007)\"\" \"About 
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2 sqrt 5/7 - 3 sqrt 7/5 + sqrt 140
\n" ); document.write( "2sqrt(5)/sqrt(7) * sqrt(7)/sqrt(7) = 2sqrt(35)/7 Rationalize the denoinator
\n" ); document.write( "3sqrt(7)/sqrt(5) * sqrt(5)/sqrt(5) = 3sqrt(35)/5
\n" ); document.write( "sqrt(140)=sqrt(4*35)=2sqrt(35)
\n" ); document.write( "2sqrt(35)/7-3sqrt(35)/5+2sqrt(35)
\n" ); document.write( "=(10sqrt(35)-21sqrt(35)+70sqrt(35))/35
\n" ); document.write( "=59sqrt(35)/35
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