document.write( "Question 473619: i) Express \"6+%2B+4x+-+x%5E2\" in the form \"a+-+%28x+%2B+b%29%5E2\", where a and b are integers.
\n" ); document.write( "ii) Find the coordinates of the turning point of the curve \"y+=+6+%2B+4x+-+x%5E2\" and determine the nature of this turning point.\r
\n" ); document.write( "\n" ); document.write( "*Please answer as soon as possible bro :)
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Algebra.Com's Answer #325146 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Find the coordinates of the turning point of the curve
\n" ); document.write( "\"y+=+-x%5E2+%2B4x%2B6\" |Turning point is the Vertex of the Parabola
\n" ); document.write( " y = -[x^2 - 4x] + 6
\n" ); document.write( " y = -[(x-2)^2 - 4] + 6
\n" ); document.write( " y = -(x-2)^2 + 10 V(2,10), the turning point
\n" ); document.write( " a = -1 -1<0, Parabola opens downward, turning point is a maximum\r
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