document.write( "Question 474084: Find the coordinates of the turning point of the curve \"y+=+6+%2B+4x+-+x%5E2\" (by expressing this equation in the form \"a+-+%28x+%2B+b%29%5E2\" ) and determine the nature of this turning point.
\n" ); document.write( "*Please answer as soon as possible bro :)
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Algebra.Com's Answer #325140 by nerdybill(7384)\"\" \"About 
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\"y+=+6+%2B+4x+-+x%5E2\"
\n" ); document.write( "\"turning point\" is at the vertex, where the x coordinate is at:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -4/(2(-1))
\n" ); document.write( "x = -4/(-2)
\n" ); document.write( "x = 2
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\n" ); document.write( "find y by plugging it into equation:
\n" ); document.write( "\"y+=+6+%2B+4x+-+x%5E2\"
\n" ); document.write( "\"y+=+6+%2B+4%282%29+-+2%5E2\"
\n" ); document.write( "\"y+=+6+%2B+8+-+4\"
\n" ); document.write( "\"y+=+10\"
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\n" ); document.write( "turning point is at (2,10)
\n" ); document.write( "Since the coefficient associated with the x^2 is negative, it is a parabola that opens downwards.
\n" ); document.write( "This means (2,10) is the peak.
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