document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=474053>Question 474053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you express this series in summation notation?\r<BR>\n" );
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document.write( "-(1)/(2)+(1)/(4)+(-1)/(6)+(1)/(8)+(-1)/(10) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325120 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you express this series in summation notation? <BR>\n" );
document.write( "-(1)/(2)+(1)/(4)+(-1)/(6)+(1)/(8)+(-1)/(10)<BR>\n" );
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document.write( "Take care of the signs: (-1)^n<BR>\n" );
document.write( "Take of the numerator: 1<BR>\n" );
document.write( "Take care of the denominator:(n)(n+1)<BR>\n" );
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document.write( "Summation[(-1)^n(1/[n(n+1)]]<BR>\n" );
document.write( "for n = 1 to oo\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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