document.write( "Question 6072: is this correct?\r
\n" ); document.write( "\n" ); document.write( "f(x+1) for sqrt x^2+x\r
\n" ); document.write( "\n" ); document.write( "=sqrt (x+1)^2+X+1
\n" ); document.write( "=sqrt x^2+2x+1+x+1
\n" ); document.write( "=sqrt x^2+3x+2
\n" ); document.write( "=2sqrt3x+1\r
\n" ); document.write( "\n" ); document.write( "thanks!!
\n" ); document.write( "

Algebra.Com's Answer #3251 by Abbey(339)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "f(x+1) for \"sqrt+%28x%5E2%2Bx%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"sqrt%28+%28x%2B1%29%5E2%2BX%2B1%29\"
\n" ); document.write( "=\"sqrt%28+x%5E2%2B2x%2B1%2Bx%2B1%29\"
\n" ); document.write( "=\"sqrt+%28x%5E2%2B3x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "You were correct up to here:
\n" ); document.write( "=\"2%2Asqrt%283x%2B1%29\"
\n" ); document.write( "the 2 does not come out of the square root, so your answer should have stayed =\"sqrt%28+x%5E2%2B3x%2B2%29\"
\n" ); document.write( "
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