document.write( "Question 473952: log10^7+log10(3n-2)=log10(6n+1) \n" ); document.write( "

Algebra.Com's Answer #325098 by stanbon(75887) $\"\"$ $\"About$

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log10^7+log10(3n-2)=log10(6n+1)\r
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\n" ); document.write( "log10^7 = log10(6n+1)-log10(3n-2)
\n" ); document.write( "--------
\n" ); document.write( "log10[(6n+1)/(3n-2)] = 7
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\n" ); document.write( "(6n+1)/(3n-2) = 10^7
\n" ); document.write( "etc.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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