document.write( "Question 473957: A biker bikes 2.7 hours to the city. Bikerbikes .9 hrs more coming back at 3 miles per hours slower. What is the total distance biker biked? \n" ); document.write( "
Algebra.Com's Answer #325081 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = biker's speed going to city
\n" ); document.write( "given:
\n" ); document.write( "Time going to city is \"+t+=+2.7+\" hrs
\n" ); document.write( "\"+d+=+s%2At+\"
\n" ); document.write( "\"+d+=+s%2A2.7+\"
\n" ); document.write( "---------------
\n" ); document.write( "Coming back from city is the same distance, so
\n" ); document.write( "\"+d+=+%28+s+-+3%29%2A%282.7+%2B+.9%29+\"
\n" ); document.write( "\"+d+=+2.7s+-+8.1+%2B+.9s+-+2.7+\"
\n" ); document.write( "\"+d+=+3.6s+-+10.8+\"
\n" ); document.write( "---------------
\n" ); document.write( "Since the distances are equal,
\n" ); document.write( "\"+s%2A2.7+=+3.6s+-+10.8+\"
\n" ); document.write( "Subtract \"+2.7s+\" from both sides
\n" ); document.write( "\"+0+=+.9s+-+10.8+\"
\n" ); document.write( "Add \"+10.8+\" to both sides
\n" ); document.write( "\"+.9s+=+10.8+\"
\n" ); document.write( "\"+s+=+12+\"
\n" ); document.write( "--------------
\n" ); document.write( "Now find \"+d+\"
\n" ); document.write( "\"+d+=+2.7s+\"
\n" ); document.write( "\"+d+=+2.7%2A12+\"
\n" ); document.write( "\"+d+=+32.4+\"
\n" ); document.write( "--------------
\n" ); document.write( "Since the biker went to the city and
\n" ); document.write( "then back again, you need to find \"+2d+\"
\n" ); document.write( "\"+2d+=+2%2A32.4+\"
\n" ); document.write( "\"+2d+=+64.8+\"
\n" ); document.write( "The total distance biked is 64.8 mi
\n" ); document.write( "check:
\n" ); document.write( "\"+d+=+%28+s+-+3%29%2A%282.7+%2B+.9%29+\"
\n" ); document.write( "\"+d+=+%28+12+-+3%29%2A%282.7+%2B+.9%29+\"
\n" ); document.write( "\"+d+=+9%2A3.6+\"
\n" ); document.write( "\"+d+=+32.4+\"
\n" ); document.write( "\"+2d+=+64.8+\"
\n" ); document.write( "OK \n" ); document.write( "
\n" );