document.write( "Question 473939: How do i solve this log5^7+1/2log5^4=log5^x \n" ); document.write( "
Algebra.Com's Answer #325073 by ccs2011(207)\"\" \"About 
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Use the following log rules:
\n" ); document.write( "log(a) + log(b) = log(ab)
\n" ); document.write( "log(a) - log(b) = log(a/b)
\n" ); document.write( "log(a^n) = n*log(a)
\n" ); document.write( "--> \"log+5%5E7+=+7%2Alog+5\"
\n" ); document.write( "--> \"%281%2F2%29log+5%5E4+=+%284%29%281%2F2%29log+5+=+2%2Alog+5\"
\n" ); document.write( "--> \"log+5%5Ex+=+x%2Alog+5\"
\n" ); document.write( "Now the equation looks like this:
\n" ); document.write( "\"7%2Alog+5+%2B+2%2Alog+5+=+x%2Alog+5\"
\n" ); document.write( "Add like terms
\n" ); document.write( "\"9%2Alog+5+=+x%2Alog+5\"
\n" ); document.write( "Divide by log(5) on both sides
\n" ); document.write( "\"9+=+x\"
\n" ); document.write( "Solution is x = 9
\n" ); document.write( "
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