document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473909>Question 473909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> refer to equaliateral if tringle ABC which has perimiter is 39 centermiter . If the midle point of the  side conecting midpoints of conecting midle point of side and drawing new tringles is indefinitely.<BR>\n" );
document.write( "a)write an infinite geometric series to represent the sum of the perimeter of all of the triangle. <BR>\n" );
document.write( "b) Find the sum of the perimeter of all triangles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #325040 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=325040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) 3*(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=13+%2B+13%2F2+%2B+13%2F2%5E2+%2B+13%2F2%5E3 ALIGN=MIDDLE  ALT=\"13+%2B+13%2F2+%2B+13%2F2%5E2+%2B+13%2F2%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >+...)\r<BR>\n" );
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document.write( "b)  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2A%2813%2F%281-1%2F2%29%29+=+3%2A13%2A2+=+78 ALIGN=MIDDLE  ALT=\"3%2A%2813%2F%281-1%2F2%29%29+=+3%2A13%2A2+=+78\"   DISABLED_style= \"max-width:90%; height:auto;\" > centimeters. </SPAN>\n" );
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