document.write( "Question 473886: Another problem I need help with\r
\n" ); document.write( "\n" ); document.write( "In a recent year, the mean number of strokes per hole for a famous golfer was approximately 3.8.
\n" ); document.write( " Find the variance and standard deviation using the fact that the variance of a Poisson distribution is σ2=μ.
\n" ); document.write( " How likely is this golfer to play an 18-hole round have more than 72 strokes?
\n" ); document.write( " The variance is= (round to the nearest tenth as needed)
\n" ); document.write( " The Standard deviation is_________ Strokes. (round to the nearest then as needed.)
\n" ); document.write( " The probability of more than 72 strokes in an 18-hole is____(round to the nearest thousandth as needed)
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #325033 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"mu+=+sigma%5E2+=+3.8%2A18+=+68.4\"
\n" ); document.write( "==> \"sigma+=+sqrt%2868.4%29+=+8.3\"\r
\n" ); document.write( "\n" ); document.write( "==> The probability of more than 72 strokes in an 18-hole = \"1-e%5E%28-68.4%29%2Asum%2868.4%5Ex%2Fx%21%2C+x+=+0%2C+72%29\".
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