document.write( "Question 473811: During the first part of a trip a canoeist travels 95 miles at a certain speed. The canoeist travels 22 miles on the second part of the trip at a speed of 5 mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #325024 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! During the first part of a trip a canoeist travels 95 miles at a certain speed. \n" ); document.write( " The canoeist travels 22 miles on the second part of the trip at a speed of 5 mph slower. \n" ); document.write( " The total time for the trip is 3 hrs. What was the speed on each part of the trip? \n" ); document.write( ": \n" ); document.write( "A totally unrealistic problem, a canoe that cover over 100 mi in 3 hrs!! \n" ); document.write( "But anyway: \n" ); document.write( ": \n" ); document.write( "Let s = speed for the 1st part of 95 mi \n" ); document.write( "then \n" ); document.write( "(s-5) = speed for the 2nd part of 22 mi \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( "1st part time + 2nd part time = 3 hrs \n" ); document.write( " \n" ); document.write( "multiply by s(s-5), resulting in: \n" ); document.write( "95(s-5) + 22s = 3s(s-5) \n" ); document.write( ": \n" ); document.write( "95s - 475 + 22s = 3s^2 - 15s \n" ); document.write( "117s - 475 = 3s^2 - 15s \n" ); document.write( "0 = 3s^2 - 15s - 117s + 475 \n" ); document.write( "A quadratic equation \n" ); document.write( "3s^2 - 132s + 475 = 0 \n" ); document.write( "use the quadratic formula \n" ); document.write( " \n" ); document.write( "a=3; b=-132; c=475 \n" ); document.write( " \n" ); document.write( "You do the math to find s, only one of the solutions will make sense \n" ); document.write( " \n" ); document.write( " |