document.write( "Question 473811: During the first part of a trip a canoeist travels 95 miles at a certain speed. The canoeist travels 22 miles on the second part of the trip at a speed of 5 mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #325024 by ankor@dixie-net.com(22740)\"\" \"About 
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During the first part of a trip a canoeist travels 95 miles at a certain speed.
\n" ); document.write( " The canoeist travels 22 miles on the second part of the trip at a speed of 5 mph slower.
\n" ); document.write( " The total time for the trip is 3 hrs. What was the speed on each part of the trip?
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\n" ); document.write( "A totally unrealistic problem, a canoe that cover over 100 mi in 3 hrs!!
\n" ); document.write( "But anyway:
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\n" ); document.write( "Let s = speed for the 1st part of 95 mi
\n" ); document.write( "then
\n" ); document.write( "(s-5) = speed for the 2nd part of 22 mi
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\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "1st part time + 2nd part time = 3 hrs
\n" ); document.write( "\"95%2Fs\" + \"22%2F%28%28s-5%29%29\" = 3
\n" ); document.write( "multiply by s(s-5), resulting in:
\n" ); document.write( "95(s-5) + 22s = 3s(s-5)
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\n" ); document.write( "95s - 475 + 22s = 3s^2 - 15s
\n" ); document.write( "117s - 475 = 3s^2 - 15s
\n" ); document.write( "0 = 3s^2 - 15s - 117s + 475
\n" ); document.write( "A quadratic equation
\n" ); document.write( "3s^2 - 132s + 475 = 0
\n" ); document.write( "use the quadratic formula
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=3; b=-132; c=475
\n" ); document.write( "\"x+=+%28-%28-132%29+%2B-+sqrt%28132%5E2-4%2A3%2A475+%29%29%2F%282%2A3%29+\"
\n" ); document.write( "You do the math to find s, only one of the solutions will make sense
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