document.write( "Question 473898: the length of a rectangle is 3 more than twice its width. if the perimeter is 54 inches, what is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #325015 by algebrahouse.com(1659)\"\" \"About 
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\"the length of a rectangle is 3 more than twice its width. if the perimeter is 54 inches, what is the width of the rectangle?\"\r
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\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "2x + 3 = length {length is 3 more than twice width}\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle is 2(width) + 2(length)\r
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\n" ); document.write( "\n" ); document.write( "2x + 2(2x + 3) = 54 {perimeter = 2(width) + 2(length)}
\n" ); document.write( "2x + 4x + 6 = 54 {used distributive property}
\n" ); document.write( "6x + 6 = 54 {combined like terms}
\n" ); document.write( "6x = 48 {subtracted 6 from both sides}
\n" ); document.write( "x = 8 {divided both sides by 6}
\n" ); document.write( "2x + 3 = 19 {substituted 8, in for x, into 2x + 3}\r
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\n" ); document.write( "\n" ); document.write( "width = 8 and length = 19
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