document.write( "Question 6087: This question is on the Addition Method rather than the Substitution Method. When using the Addition Method won't you only solve for 1 variable? Here is the problem below:
\n" ); document.write( "Problem:
\n" ); document.write( "(Eq.1) 3a + 2b = 8
\n" ); document.write( "(Eq.2) 5a + 2b =2\r
\n" ); document.write( "\n" ); document.write( "-1(3a) + -1(2b) = -1(8)\r
\n" ); document.write( "\n" ); document.write( " -3a + -2b = -8
\n" ); document.write( " 5a + 2b = 2
\n" ); document.write( " _______________
\n" ); document.write( " 2a = -6
\n" ); document.write( " 2a/2 = -6/2
\n" ); document.write( " a = -3
\n" ); document.write( "If I canceled out \"b\" how do I solve for \"b\". \r
\n" ); document.write( "\n" ); document.write( "My instructor wrote this on my test:\r
\n" ); document.write( "\n" ); document.write( "b=?\r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( "TSJ
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #3250 by guapa(62)\"\" \"About 
You can put this solution on YOUR website!
You always solve for both variables.
\n" ); document.write( "You did a great job by solving for a. In order to find b you just have to substitute a for -3 in any of the original equation. Just choose the one that is the easiest to solve for you.
\n" ); document.write( "\"3a%2B2b=8\"
\n" ); document.write( "\"2b=8-3a\"
\n" ); document.write( "\"b=%288-3a%29%2F2\"
\n" ); document.write( "\"b=%288-3%28-3%29%29%2F2\"
\n" ); document.write( "\"b=%288%2B9%29%2F2\"
\n" ); document.write( "\"b=17%2F2\"
\n" ); document.write( "Hope it helps
\n" ); document.write( "
\n" );