document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473852>Question 473852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth $50 a pound that she wants to mix with 90 pounds of coffee worth $80 a pound to get a mixture that can be sold for $70 a pound. How many pounds of the $50 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324999 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a merchant has coffee worth $50 a pound that she wants to mix with 90 pounds of coffee worth $80 a pound to get a mixture that can be sold for $70 a pound. How many pounds of the $50 coffee should be used?Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "50x + 80*90 = 70(x+90)<BR>\n" );
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document.write( "50x + 80*90 = 70x + 70*90<BR>\n" );
document.write( "----<BR>\n" );
document.write( "20x = 10*90<BR>\n" );
document.write( "x = 45 lbs (amt. of $50 coffee needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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