document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473735>Question 473735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> show all work using the 5-step method to solve:\r<BR>\n" );
document.write( "\n" );
document.write( "a sailboat travels 20 miles downstream in 4 hours. it returns in 5 hours. find the speed of the sailboat in still water and the rate of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324951 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = rate*time denoted as d=rt<BR>\n" );
document.write( "The boat traveled the same distance of 20 miles both upstream and downstream.<BR>\n" );
document.write( "Let s be speed of boat in still water, let c be rate of current.<BR>\n" );
document.write( "Downstream boat goes faster so its speed is s+c, Upstream its s - c.<BR>\n" );
document.write( "Set up equations:<BR>\n" );
document.write( "20 = 4(s+c)<BR>\n" );
document.write( "20 = 5(s-c)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "20 = 4s + 4c<BR>\n" );
document.write( "20 = 5s - 5c<BR>\n" );
document.write( "Using substitution <BR>\n" );
document.write( "5s - 5c = 4s + 4c<BR>\n" );
document.write( "Solve for s: (Subtract 4s on both sides, Add 5c on both sides)<BR>\n" );
document.write( "s = 9c<BR>\n" );
document.write( "Now substitute 9c in for s:<BR>\n" );
document.write( "20 = 4(9c) + 4c<BR>\n" );
document.write( "20 = 36c + 4c<BR>\n" );
document.write( "20 = 40c<BR>\n" );
document.write( "1/2 = c<BR>\n" );
document.write( "--> s = 9(1/2) = 9/2 = 4.5<BR>\n" );
document.write( "Therefore the boat travels 4.5 mph in still water and the rate of the current is 0.5 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );