document.write( "Question 473736: A city council with nine members must appoint a three person subcommittee. How many subcommittees are possible? \n" ); document.write( "
Algebra.Com's Answer #324948 by ccs2011(207)\"\" \"About 
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This will be solved using combinations because there is no order within the sub-committees.
\n" ); document.write( "How many groups of 3 can be made from 9 members.
\n" ); document.write( "Combination formula:
\n" ); document.write( "9C3 = \"9%21%2F%28%289-3%29%21%2A3%21%29+=+9%21%2F%286%21%2A3%21%29\"
\n" ); document.write( "9! can be written as 9*8*7*6!
\n" ); document.write( "Notice that the 6! can be cancelled on top and bottom, leaving
\n" ); document.write( "\"%289%2A8%2A7%29%2F%283%2A2%2A1%29\"
\n" ); document.write( "You can simplify things by doing more cancelling, \"9%2F3+=+3\", \"8%2F2+=+4\"
\n" ); document.write( "=\"3%2A4%2A7+=+12%2A7+=+84\"
\n" ); document.write( "Therefore there are 84 sub-committees possible.
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