document.write( "Question 472970: Find the equation in standard form of an ellipse with center at (0,0) minor axis of length 18, and foci at (0,-12) and (0,12).\r
\n" );
document.write( "\n" );
document.write( "a. (x^2/225)+(y^2/81)=1
\n" );
document.write( "b. (x^2/144)+(y^2/81)=1
\n" );
document.write( "c. (x^2/81)+(y^2/225)=1
\n" );
document.write( "d. (x^2/9)+(y^2/15)=1
\n" );
document.write( "e. (x^2/15)+(y^2/9)=1 \n" );
document.write( "
Algebra.Com's Answer #324836 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the equation in standard form of an ellipse with center at (0,0) minor axis of length 18, and foci at (0,-12) and (0,12). \n" ); document.write( "a. (x^2/225)+(y^2/81)=1 \n" ); document.write( "b. (x^2/144)+(y^2/81)=1 \n" ); document.write( "c. (x^2/81)+(y^2/225)=1 \n" ); document.write( "d. (x^2/9)+(y^2/15)=1 \n" ); document.write( "e. (x^2/15)+(y^2/9)=1 \n" ); document.write( "** \n" ); document.write( "As noted from foci, where x doesn't change but y does, given ellipse has a vertical major axis with standard form: (x-h)^2/b^2+(y-k)^2/a^2=1, (a>b) \n" ); document.write( "2b=minor axis=18 \n" ); document.write( "b=9 \n" ); document.write( "b^2=81 \n" ); document.write( ".. \n" ); document.write( "c=12 \n" ); document.write( "c^2=a^2-b^2 \n" ); document.write( "144=a^2-81 \n" ); document.write( "a^2=144+81=225 \n" ); document.write( "a=√225=15 \n" ); document.write( ".. \n" ); document.write( "Equation: \n" ); document.write( "x^2/81+y^2/225=1 \n" ); document.write( "c. is the correct ans. \n" ); document.write( " |