document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473615>Question 473615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve<BR>\n" );
document.write( "i) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28base3%29%282x+%2B+1%29+=+2+%2B+log+%28base3%29+%283x+-+11%29 ALIGN=MIDDLE  ALT=\"log%28base3%29%282x+%2B+1%29+=+2+%2B+log+%28base3%29+%283x+-+11%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "ii) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%28base4%29y+%2B+log+%28base2%29y+=+9+ ALIGN=MIDDLE  ALT=\"log%28base4%29y+%2B+log+%28base2%29y+=+9+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "*Please answer as soon as possible bro :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324833 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i) log(base3)(2x + 1) = 2 + log (base3) (3x - 11)<BR>\n" );
document.write( "ii)log(base4)y + log (base2)y = 9 <BR>\n" );
document.write( "**<BR>\n" );
document.write( "i) log3(2x+1)=2+log3(3x-11)<BR>\n" );
document.write( "log3(2x+1)-log3(3x-11)=2<BR>\n" );
document.write( "log3[(2x+1)/(3x-11)]=2<BR>\n" );
document.write( "convert to exponential form: (base(3) raised to log of number(2)=number(2x+1)/(3x-11)<BR>\n" );
document.write( "3^2=(2x+1)/(3x-11)=9<BR>\n" );
document.write( "2x+1=27x-99<BR>\n" );
document.write( "25x=100<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "log3(2x+1)=2+log3(3x-11)<BR>\n" );
document.write( "log3(8+1)=2+log3(12-11)<BR>\n" );
document.write( "log3(9)=2+log3(1)<BR>\n" );
document.write( "2=2+0<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ii)log4y+log2y=9<BR>\n" );
document.write( "change to base 2<BR>\n" );
document.write( "log2y/log2(4)+log2y=9<BR>\n" );
document.write( "log2y/2+log2y=9<BR>\n" );
document.write( "LCD:2<BR>\n" );
document.write( "log2y+2log2y=18<BR>\n" );
document.write( "3log2y=18<BR>\n" );
document.write( "log2y=6<BR>\n" );
document.write( "convert to exponential form: (base(2) raised to log of number(6)=number (y)<BR>\n" );
document.write( "2^6=y<BR>\n" );
document.write( "y=64<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "log4y+log2y<BR>\n" );
document.write( "log4(64)+log2(64)=3+6=9<BR>\n" );
document.write( "                   </SPAN>\n" );
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