document.write( "Question 473602: Solve for x. (base is the x-3)\r
\n" ); document.write( "\n" ); document.write( "1+(4/3)log[x-3]4=11/3\r
\n" ); document.write( "\n" ); document.write( "Help please. \n" ); document.write( "
Algebra.Com's Answer #324832 by rmnavalta(7)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"1%2B%284%2F3%29log%28%28x-3%29%2C4%29=%2811%2F3%29\"     1. Add -1 to both sides of the equation.
\n" ); document.write( "\"%284%2F3%29log%28%28x-3%29%2C4%29=%2811%2F3%29-1\"     2. Simplify 11/3 – 1.
\n" ); document.write( "\"%284%2F3%29log%28%28x-3%29%2C4%29=%2811-3%29%2F3\"
\n" ); document.write( "\"%284%2F3%29log%28%28x-3%29%2C4%29=8%2F3\"              3. Multiply both sides of the equation by ¾.
\n" ); document.write( "\"%284%2F3%29log%28%28x-3%29%2C4%29=%288%2F3%29%29%283%2F4%29\"
\n" ); document.write( "\"log%28%28x-3%29%2C4%29=%288%2F4%29\"
\n" ); document.write( "\"log%28%28x-3%29%2C4%29=2\"                     4. Convert logarithm to exponential form. y=log[b]x is equivalent to x=b^y.
\n" ); document.write( "\"%28x-3%29%5E2=4\"                          5. Expand (x-3)^2. (x-3)^2=x^2-6x+9.
\n" ); document.write( "\"x%5E2-6x%2B9=4\"                      6. Add -4 to both sides.
\n" ); document.write( "\"x%5E2-6x%2B9-4=4-4\"
\n" ); document.write( "\"x%5E2-6x%2B5=0\"                      7. The resulting equation is a quadratic equation. Solve this by factoring.
\n" ); document.write( "\"%28x-5%29%28x-1%29=0\"                  8. Use zero product property to solve for the value(s) of x. Equate each factor to 0.

\n" ); document.write( "x-5=0 or x-1=0

\n" ); document.write( "x=5 or x=1                          9. The values of x are 5 or 1.
\n" ); document.write( "x=1 should be disregarded or is not a solution because it will yield to a negative base which is 1-3=-2. Logarithm can not have a negative base.
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\n" ); document.write( "(ANSWER: x=5)
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