document.write( "Question 473602: Solve for x. (base is the x-3)\r
\n" ); document.write( "\n" ); document.write( "1+(4/3)log[x-3]4=11/3\r
\n" ); document.write( "\n" ); document.write( "Help please.
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Algebra.Com's Answer #324831 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Solve for x. (base is the x-3)
\n" ); document.write( "1+4/3log(x-3)4=11/3
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\n" ); document.write( "1+4/3log(x-3)4=11/3
\n" ); document.write( "4/3log(x-3)4=11/3-1
\n" ); document.write( "4/3log(x-3)4=11/3-3/3=8/3
\n" ); document.write( "log(x-3)4=24/12=2
\n" ); document.write( "convert to exponential form: (base(x-3) raised to log of number(2)=number(4)
\n" ); document.write( "(x-3)^2=4
\n" ); document.write( "x^2-6x+9=4
\n" ); document.write( "x^2-6x+5=0
\n" ); document.write( "(x-5)(x-1)=0
\n" ); document.write( "x=5
\n" ); document.write( "or
\n" ); document.write( "x=1 (reject, (x-3)>1)
\n" ); document.write( "Check: For x=5
\n" ); document.write( "1+4/3log(x-3)4
\n" ); document.write( "1+4/3log(5-3)4
\n" ); document.write( "1+4/3log(2)4
\n" ); document.write( "1+(4/3)*2=8/3+1=8/3+3/3=11/3
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