document.write( "Question 473539: Dear math teacher, \r
\n" ); document.write( "\n" ); document.write( "Would you please help me solve this problem? \r
\n" ); document.write( "\n" ); document.write( "Find n if
\n" ); document.write( "3times {(2n+4)Permutation3} = 2times {(n+4)Permutation4}\r
\n" ); document.write( "\n" ); document.write( "Here is what I got:
\n" ); document.write( "3 times (2n+4) times (2n+3) times (2n+2) = 2 times (n+4) times (n+3) times (n+2) times (n+1)\r
\n" ); document.write( "\n" ); document.write( "But then I am not sure how to isolate n on one side of the equation to solve for it. The correct answer is: 6. \r
\n" ); document.write( "\n" ); document.write( "Thank you very much for your time and effort in helping me with my homework. \r
\n" ); document.write( "\n" ); document.write( "I.
\n" ); document.write( "

Algebra.Com's Answer #324774 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
Looks good so far!
\n" ); document.write( "To isolate n you need to multiply everything out, then simplify by adding like terms
\n" ); document.write( "You should end up with a 4th degree polynomial:
\n" ); document.write( "\"n%5E4+-+2n%5E3+-+19n%5E2+-+28n+-+12+=+0\"
\n" ); document.write( "Now n must be a positive integer because we are dealing with a permutation.
\n" ); document.write( "Use synthetic division to try to factor out a factor of 12.
\n" ); document.write( "Try 1,2,3,4,6,12 these are the only possible solutions.
\n" ); document.write( "If you get a zero remainder then its the solution.
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