document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473522>Question 473522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the horizontal sides of a rectangle are one half the length of the side of a particular square. The vertical sides of the rectangle are 4 cm more than 3 times the side of the square. If the perimeter of the rectangle is twice the perimeter of the square, what are the demensisions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324750 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the side of the square be x.<BR>\n" );
document.write( "Then the dimensions of the rectangle are: 1/2x and 3x +4<BR>\n" );
document.write( "Perimeter of square = 4x<BR>\n" );
document.write( "Perimeter of rectangle = 1/2x + 1/2x + (3x+4) +(3x+4) = 7x + 8<BR>\n" );
document.write( "Twice the perimeter of square is 8x.<BR>\n" );
document.write( "Then equation is:<BR>\n" );
document.write( "8x = 7x + 8<BR>\n" );
document.write( "Subtract 7x on both sides<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "--> 1/2(8) = 4, 3(8)+4 = 28<BR>\n" );
document.write( "Therefore dimensions of rectangle are 28 by 4. </SPAN>\n" );
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