document.write( "Question 473513: Solve the absolute value inequality. Write the answer in interval notation. The problem is: |5-2x over 6|< or equal to 3 - can you show me how to solve this. I thought you have to multiply the 6 by all the numbers, but I'm not getting the correct answer. Thanks. \n" ); document.write( "
Algebra.Com's Answer #324748 by ccs2011(207)\"\" \"About 
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\"abs%28%285-2x%29%2F6%29+%3C=+3\"
\n" ); document.write( "Since we are dealing with an absolute value you have to deal with the negative case as well.
\n" ); document.write( "\"%285-2x%29%2F6\" can be any number from -3 to 3 because the absolute value turn all the negative values positive
\n" ); document.write( "Rewrite inequality without absolute value signs
\n" ); document.write( "\"-3+%3C=+%285-2x%29%2F6+%3C=+3\"
\n" ); document.write( "Now you multiply equation by 6
\n" ); document.write( "\"-18+%3C=+5-2x+%3C=+18\"
\n" ); document.write( "Subtract 5 from both sides
\n" ); document.write( "\"-23+%3C=+-2x+%3C=+13\"
\n" ); document.write( "Divide by -2 on both sides
\n" ); document.write( "**Important: when dividing by a negative flip the inequality**
\n" ); document.write( "EX: -x < 3 = x > -3 , If you change the sign then flip the inequality.
\n" ); document.write( "After dividing and flipping the inequality
\n" ); document.write( "\"23%2F2+%3E=+x+%3E=+-13%2F2\"
\n" ); document.write( "Interval notation, use brackets for \">=\" parenthesis for \">\"
\n" ); document.write( "x is any real number in [-6.5, 11.5]\r
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