document.write( "Question 473486: can someone help me plss before monday?\r
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document.write( "solve the equation.\r
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document.write( "17. 2x+1/3x-3 = 5x+1/6x-2 \n" );
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Algebra.Com's Answer #324699 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation is: \n" ); document.write( " \n" ); document.write( "i don't see any common factors, so i think we'll have to do this the hard way. \n" ); document.write( "cross multiply to get: \n" ); document.write( " \n" ); document.write( "multiply those factors out to get: \n" ); document.write( " \n" ); document.write( "subtract 12x^2 and 2x from both sides of the equation, and add 2 to both sides of the equation to get: \n" ); document.write( " \n" ); document.write( "combine like terms to get: \n" ); document.write( " \n" ); document.write( "this is the same as: \n" ); document.write( " \n" ); document.write( "this is a quadratic equation. \n" ); document.write( "you need the quadratic formula to solve this. \n" ); document.write( "the quadratic formula is: \n" ); document.write( "x = \n" ); document.write( "in your equation: \n" ); document.write( "a = 3 \n" ); document.write( "b = -14 \n" ); document.write( "c = -1 \n" ); document.write( "solving by using the quadratic formula gets you: \n" ); document.write( "x = 4.737034184 \n" ); document.write( "x = -.070367517 \n" ); document.write( "substitute these values of x into the original equations and you will see that the equations are true. \n" ); document.write( "those are your answer. \n" ); document.write( "this was very messy. \n" ); document.write( "i didn't see an easier way to get the answer. \n" ); document.write( " \n" ); document.write( " |