document.write( "Question 473450: I need help finding two consecutive odd integers the product of which is 143.
\n" ); document.write( "i have tried the solution n(n+2)=143 is that the proper solution?
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Algebra.Com's Answer #324671 by jim_thompson5910(35256)\"\" \"About 
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\"n%28n%2B2%29=143\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2B2n=143\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2B2n-143=0\" Subtract 143 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"n%5E2%2B2n-143\" is in the form of \"An%5E2%2BBn%2BC\" where \"A=1\", \"B=2\", and \"C=-143\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"n\":\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-%282%29+%2B-+sqrt%28+%282%29%5E2-4%281%29%28-143%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=2\", and \"C=-143\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+sqrt%28+4-4%281%29%28-143%29+%29%29%2F%282%281%29%29\" Square \"2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+sqrt%28+4--572+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-143%29\" to get \"-572\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+sqrt%28+4%2B572+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%284--572%29\" as \"sqrt%284%2B572%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+sqrt%28+576+%29%29%2F%282%281%29%29\" Add \"4\" to \"572\" to get \"576\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+sqrt%28+576+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B-+24%29%2F%282%29\" Take the square root of \"576\" to get \"24\". \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%28-2+%2B+24%29%2F%282%29\" or \"n+=+%28-2+-+24%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+%2822%29%2F%282%29\" or \"n+=++%28-26%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"n+=+11\" or \"n+=+-13\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"n+=+11\" or \"n+=+-13\"
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