document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473398>Question 473398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two persons are to run a race,but one can run 10 meters per second, whereas the other can run 6 meters per second. if the slower runner has a 70-meter head start, how long will it be before the faster runner if they began at the same time?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324663 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = rate*time<BR>\n" );
document.write( "d= r*t<BR>\n" );
document.write( "Goal is to find time it takes for faster runner to catch up with slower runner. At this time the faster runner will have traveled 70 more meters than slower runner.<BR>\n" );
document.write( "Let d1 be faster runner and d2 be slower runner.<BR>\n" );
document.write( "d1 = d2 + 70<BR>\n" );
document.write( "d1 = 10t<BR>\n" );
document.write( "d2 = 6t<BR>\n" );
document.write( "Substitute these into 1st equation and solve for t:<BR>\n" );
document.write( "10t = 6t + 70<BR>\n" );
document.write( "Subtract 10t on both sides<BR>\n" );
document.write( "4t = 70<BR>\n" );
document.write( "Divide by 4 on both sides<BR>\n" );
document.write( "t = 17.5<BR>\n" );
document.write( "Therefore, it will take 17.5 seconds for faster runner to catch up<BR>\n" );
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