document.write( "Question 473344: A man is x years old while his son is y years old.the sum of their ages is twice the difference of their ages.if the product of their ages is 675,fine the age of the man \n" ); document.write( "

Algebra.Com's Answer #324637 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
A man is x years old while his son is y years old.
\n" ); document.write( "the sum of their ages is twice the difference of their ages.
\n" ); document.write( "x + y = 2(x-y)
\n" ); document.write( "x + y = 2x - 2y
\n" ); document.write( "x - 2x = -2y - y
\n" ); document.write( "-x = -3y
\n" ); document.write( "x = 3y
\n" ); document.write( ":
\n" ); document.write( "if the product of their ages is 675,
\n" ); document.write( "x * y = 675
\n" ); document.write( "replace x with (3y)
\n" ); document.write( "y(3y) = 675
\n" ); document.write( "3y^2 = 675
\n" ); document.write( "divide both sides by 3
\n" ); document.write( "y^2 = $\"675%2F3\"$
\n" ); document.write( "y^2 = 225
\n" ); document.write( "y = $\"sqrt%28225%29\"$
\n" ); document.write( "y = 15 yrs is the son's age
\n" ); document.write( "then
\n" ); document.write( "x = 3y
\n" ); document.write( "x = 3(15)
\n" ); document.write( "x = 45 is the man's age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the product: 45 * 15 = 675\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "find the age of the man \n" ); document.write( "

\n" );