document.write( "Question 48993: please help!\r
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document.write( "How much water should be added to 50ml of 25% acid solution to dilute it to a 10% acid solution?\r
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document.write( "A 75 ml
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document.write( "B. 7.5 ml
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document.write( "C impossible to do
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #32461 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! Use this basic formula: \n" ); document.write( "(% or rate of A)(Amount of A)+ (% or rate of B)(Amount of B) = C \n" ); document.write( "C can equal (% or rate of C)(A+B) or C can equal (% or rate of C)(Amount of C) \n" ); document.write( ". \n" ); document.write( "Change percentages to decimals: Example: 10% = .10 \n" ); document.write( ". \n" ); document.write( "Water is 0% acid. \n" ); document.write( ". \n" ); document.write( "(0%)(xml) + (25%)(50ml) = (10%)(xml + 50ml) \n" ); document.write( "(0)(x) + (.25)(50) = (.10)(x + 50) \n" ); document.write( "0 + 12.50 = .10x + 5.0 \n" ); document.write( "12.50 = .10x + 5.0 [Solve for \"x\"] \n" ); document.write( "7.5 = .10x \n" ); document.write( "75ml = x \n" ); document.write( "So, add 75ml of water (0% acid) to 50ml of a 25% acid to yield 125ml of a 10% acid. \n" ); document.write( ". \n" ); document.write( "Check by plugging in all of the variables back into the original equation: \n" ); document.write( "(%A)(Amount A) + (%B)(Amount B) = (%C)(A+B) \n" ); document.write( "(0%)(75) + (.25)(50) = (.10)(125) \n" ); document.write( "12.5 = 12.5 [Checks out]\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |