document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=473295>Question 473295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x-6)/(x+5) = (x-4)/(3x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324596 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-6)/(x+5) = (x-4)/(3x+2)<BR>\n" );
document.write( "(x-6)(3x+2)=(x-4)(x+5)<BR>\n" );
document.write( "3x^2-16x-12=x^2+x-20<BR>\n" );
document.write( "2x^2-17x+8=0<BR>\n" );
document.write( "8*2=16, two factors of 16 whose sum is -17 are -16 and -1<BR>\n" );
document.write( "2x^2-x-16x+8=0<BR>\n" );
document.write( "x(2x-1)-8(2x-1)=0 factoring by grouping.<BR>\n" );
document.write( "(x-8)(2x-1)=0<BR>\n" );
document.write( "x=8, x=1/2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );