document.write( "Question 48990: How do you find the Powers of the base i? \n" ); document.write( "
Algebra.Com's Answer #32459 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
i^0 = 1
\n" ); document.write( "i^1 = i
\n" ); document.write( "i^2 = -1
\n" ); document.write( "i^3 = -i
\n" ); document.write( "i^4 = (i^2)(i^2) = (-1)(-1) = 1
\n" ); document.write( "i^5 = (i^2)(i^2)i = i
\n" ); document.write( "i^6 = (i^2)^3 = (-1)^3 = -1
\n" ); document.write( "i^7 = (i^2)^3 * i = -i
\n" ); document.write( "See a pattern?
\n" ); document.write( "Every imaginery number to an odd power = +- i
\n" ); document.write( "Every imaginery number to an even power including zero = +- 1
\n" ); document.write( "To find the value ~> just simplify
\n" ); document.write( "ex.) i^49 we know that this will equal either 'i' or '-i'
\n" ); document.write( "(i^7)^7 = (i^2*i^2*i^2*i)^7 = (-i)^7 = i
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