document.write( "Question 473272: a 10% acid solution is to be mixed with a 50% solution to get 200 litres of a 20% solution. how many litres of each solution should be used? \n" ); document.write( "
Algebra.Com's Answer #324585 by NancyLam(35)\"\" \"About 
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a 10% acid solution is to be mixed with a 50% solution to get 200 litres of a 20% solution. how many litres of each solution should be used?
\n" ); document.write( "let x = 10%
\n" ); document.write( "let y = 50%
\n" ); document.write( "x + y = 200
\n" ); document.write( " y= 200 -x
\n" ); document.write( "0.10x+0.50y = 200* 0.20
\n" ); document.write( " substitution : y= 200 -x
\n" ); document.write( "0.10x+0.50(200-x) = 200* 0.20
\n" ); document.write( "0.10x + 100- 0.50x = 40
\n" ); document.write( " -0.4x = 40 -100
\n" ); document.write( " x= -60/-0.4
\n" ); document.write( " x=15
\n" ); document.write( "substitution : x = 15 find y
\n" ); document.write( "15 + y = 200
\n" ); document.write( " y = 200-15
\n" ); document.write( " y = 185\r
\n" ); document.write( "\n" ); document.write( "10% acid solution is should be used 15 litres
\n" ); document.write( "50% acid solution is should be used 185 litres
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