document.write( "Question 48991: I need help. I need to state the range of the function f(x)= (x-2)^2 + 1
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document.write( "I have solved it this far.....
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document.write( "(x-2) (x-2) + 1\r
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document.write( "x^2-2x-2x+4 +1\r
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document.write( "x^2-4x+5 and then I equaled it to zero.
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document.write( "X^2-4x + 5 = 0\r
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document.write( "Now, I am stuck. Am I doing it right? If I am finding the range I am trying to find Y, right? So I need to solve x so I can find y. But what if I can not go any further? \n" );
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Algebra.Com's Answer #32456 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! x^2 - 4x + 5 is a parabola with a vertex of (-b/2a,f(x)) \n" ); document.write( "vertex:(2,1) and the parabola opens up \n" ); document.write( "Range: \n" ); document.write( " |