document.write( "Question 473258: a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50% solution
\n" ); document.write( "how much gallons of solution is needed
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Algebra.Com's Answer #324549 by stanbon(75887)\"\" \"About 
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a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50% solution
\n" ); document.write( "how much gallons of solution is needed
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.70x + 0.40(90-x) = 0.50*90
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "70x + 40*90 - 40x = 50*90
\n" ); document.write( "50x = 10*90
\n" ); document.write( "x = 18 gallons (amt. of 40% solution needed)
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\n" ); document.write( "90-18 = 72 gallons (amt. of 70% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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