document.write( "Question 473258: a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50% solution
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document.write( "how much gallons of solution is needed \n" );
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Algebra.Com's Answer #324549 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a 70% acid solution is to be mixed with a 40% solution to get 90 gallons of a 50% solution \n" ); document.write( "how much gallons of solution is needed \n" ); document.write( "-------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.70x + 0.40(90-x) = 0.50*90 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "70x + 40*90 - 40x = 50*90 \n" ); document.write( "50x = 10*90 \n" ); document.write( "x = 18 gallons (amt. of 40% solution needed) \n" ); document.write( "---- \n" ); document.write( "90-18 = 72 gallons (amt. of 70% solution needed) \n" ); document.write( "================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |