document.write( "Question 473172: I need help solving this equation. One side is 'x' the other 'x+12' and the hypotenuse is '60'. How can I solve this? \n" ); document.write( "

Algebra.Com's Answer #324455 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "One side is 'x' the other 'x+12' and the hypotenuse is '60'
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document.write( "Applying the Pythagorean Theorem
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document.write( " x^2 + (x+12)^2 = 3600
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document.write( "  2x^2 + 24x + 144 = 3600
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document.write( "   2x^2 + 24x -3456 = 0
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document.write( "   x^2 + 12x - 1728 = 0
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document.write( "factoring  (or using the Quadratic Formula)
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document.write( "  (x+48)(x-36) = 0
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document.write( "    (x+48)=0  x = -48  |tossing out negative solution for length
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document.write( "   (x-36) = 0 
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document.write( "     x = 36 and the other side = 48\r
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document.write( "CHECKING our Answer***
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document.write( " 1296 + 2304 = 3600 \n" );
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