document.write( "Question 473001: two circular flower beds have a combined area of 29/2pie metre. the sum of the circumferences of the two flower beds is 10pie metre. determine the radius of each flower bed. \n" ); document.write( "
Algebra.Com's Answer #324427 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! two circular flower beds have a combined area of 29/2pie metre. the sum of the circumferences of the two flower beds is 10pie metre. determine the radius of each flower bed. \n" ); document.write( ": \n" ); document.write( "Let a = radius of the 1st circular flower bed \n" ); document.write( "Let b = radius of the 2nd one \n" ); document.write( ": \n" ); document.write( "Combined areas \n" ); document.write( " \n" ); document.write( "divide thru by pi \n" ); document.write( " \n" ); document.write( "we can also write it: \n" ); document.write( "a^2 + b^2 = 14.5 \n" ); document.write( ": \n" ); document.write( "Combined Circumferences \n" ); document.write( " \n" ); document.write( "divide thru by 2pi \n" ); document.write( "a + b = 5 \n" ); document.write( "b = (5-a) \n" ); document.write( ": \n" ); document.write( "In the 1st equation replace b with (5-a) \n" ); document.write( "a^2 + (5-a)^2 = 14.5 \n" ); document.write( "a^2 + 25 - 10a + a^2 = 14.5 \n" ); document.write( "2a^2 - 10a + 25 - 14.5 = 0 \n" ); document.write( "2a^2 - 10a + 10.5 = 0 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "a^2 - 5a + 5.25 = 0 \n" ); document.write( "This factors to: \n" ); document.write( "(a-1.5)(a-3.5) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "a = 1.5, then b = 3.5 \n" ); document.write( "a = 3.5, then b = 1.5 \n" ); document.write( " |