document.write( "Question 473001: two circular flower beds have a combined area of 29/2pie metre. the sum of the circumferences of the two flower beds is 10pie metre. determine the radius of each flower bed. \n" ); document.write( "
Algebra.Com's Answer #324427 by ankor@dixie-net.com(22740)\"\" \"About 
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two circular flower beds have a combined area of 29/2pie metre. the sum of the circumferences of the two flower beds is 10pie metre. determine the radius of each flower bed.
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\n" ); document.write( "Let a = radius of the 1st circular flower bed
\n" ); document.write( "Let b = radius of the 2nd one
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\n" ); document.write( "Combined areas
\n" ); document.write( "\"pi%2Aa%5E2\" + \"pi%2Ab%5E2\" = \"29%2F2\"(\"pi\")
\n" ); document.write( "divide thru by pi
\n" ); document.write( "\"a%5E2\" + \"b%5E2\" = \"29%2F2\"
\n" ); document.write( "we can also write it:
\n" ); document.write( "a^2 + b^2 = 14.5
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\n" ); document.write( "Combined Circumferences
\n" ); document.write( "\"2%2Api%2Aa\" + \"2%2Api%2Ab\" = \"10%2Api\"
\n" ); document.write( "divide thru by 2pi
\n" ); document.write( "a + b = 5
\n" ); document.write( "b = (5-a)
\n" ); document.write( ":
\n" ); document.write( "In the 1st equation replace b with (5-a)
\n" ); document.write( "a^2 + (5-a)^2 = 14.5
\n" ); document.write( "a^2 + 25 - 10a + a^2 = 14.5
\n" ); document.write( "2a^2 - 10a + 25 - 14.5 = 0
\n" ); document.write( "2a^2 - 10a + 10.5 = 0
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "a^2 - 5a + 5.25 = 0
\n" ); document.write( "This factors to:
\n" ); document.write( "(a-1.5)(a-3.5) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "a = 1.5, then b = 3.5
\n" ); document.write( "a = 3.5, then b = 1.5
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