document.write( "Question 473111: Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #324403 by Alan3354(69443) $\"\"$ $\"About$

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Three consecutive odd integers are such that the square of the third integer is 15 more than the sum of the squares of the first two. Find the integers.
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\n" ); document.write( "The numbers are x, x+2 and x+4
\n" ); document.write( " $\"x%5E2+%2B+%28x%2B2%29%5E2+=+%28x%2B4%29%5E2+-+15\"$
\n" ); document.write( " $\"2x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+8x+%2B+1\"$
\n" ); document.write( " $\"x%5E2+-+4x+%2B+3+=+0\"$
\n" ); document.write( "(x - 1)*(x - 3) = 0
\n" ); document.write( "x = 1 --> 1, 3 & 5
\n" ); document.write( "x = 3 --> 3, 5 & 7
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