document.write( "Question 6104: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The areaof the second rectangle is 270 sq. centimeters greater than the first. What are the dimentions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #3244 by Abbey(339)\"\" \"About 
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let x = width of rectangle 1
\n" ); document.write( "let 4*x=length (it is 4 times as long as the width) of rectangle 1
\n" ); document.write( "area=length*width
\n" ); document.write( "area of rectangle 1 = \"x%2A4x=4x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "let x+2 = width of rectangle 2\r
\n" ); document.write( "\n" ); document.write( "let 4x+5 = length of rectangle 2
\n" ); document.write( "area=length*width
\n" ); document.write( "area of rectangle 2=(4x+5)(x+2)=\"4x%5E2%2B13x%2B10\"\r
\n" ); document.write( "\n" ); document.write( "area of rec.2 is 270 cm greater than rec.1
\n" ); document.write( "\"4x%5E2%2B13x%2B10=270%2B4x%5E2\"
\n" ); document.write( "subtract \"4x%5E2\" from both sides:
\n" ); document.write( "\"13x%2B10=270\"
\n" ); document.write( "subtract 10 from both sides:
\n" ); document.write( "\"13x=260\"
\n" ); document.write( "divide both sides by 13:
\n" ); document.write( "x=20
\n" ); document.write( "now plug this back into your statements:\r
\n" ); document.write( "\n" ); document.write( "let x = width of rectangle 1 = 20
\n" ); document.write( "let 4*x=length = 80\r
\n" ); document.write( "\n" ); document.write( "let x+2 = width of rectangle 2 = 22\r
\n" ); document.write( "\n" ); document.write( "let 4x+5 = length of rectangle 2 = 85\r
\n" ); document.write( "\n" ); document.write( "to check, get the area of both and find the difference
\n" ); document.write( "area 1 = 20*80=1600
\n" ); document.write( "area 2 = 22*85= 1870
\n" ); document.write( "1870-1600=270, so the answer is correct\r
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