document.write( "Question 6104: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The areaof the second rectangle is 270 sq. centimeters greater than the first. What are the dimentions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #3244 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! let x = width of rectangle 1 \n" ); document.write( "let 4*x=length (it is 4 times as long as the width) of rectangle 1 \n" ); document.write( "area=length*width \n" ); document.write( "area of rectangle 1 = \n" ); document.write( "\n" ); document.write( "let x+2 = width of rectangle 2\r \n" ); document.write( "\n" ); document.write( "let 4x+5 = length of rectangle 2 \n" ); document.write( "area=length*width \n" ); document.write( "area of rectangle 2=(4x+5)(x+2)= \n" ); document.write( "\n" ); document.write( "area of rec.2 is 270 cm greater than rec.1 \n" ); document.write( " \n" ); document.write( "subtract \n" ); document.write( " \n" ); document.write( "subtract 10 from both sides: \n" ); document.write( " \n" ); document.write( "divide both sides by 13: \n" ); document.write( "x=20 \n" ); document.write( "now plug this back into your statements:\r \n" ); document.write( "\n" ); document.write( "let x = width of rectangle 1 = 20 \n" ); document.write( "let 4*x=length = 80\r \n" ); document.write( "\n" ); document.write( "let x+2 = width of rectangle 2 = 22\r \n" ); document.write( "\n" ); document.write( "let 4x+5 = length of rectangle 2 = 85\r \n" ); document.write( "\n" ); document.write( "to check, get the area of both and find the difference \n" ); document.write( "area 1 = 20*80=1600 \n" ); document.write( "area 2 = 22*85= 1870 \n" ); document.write( "1870-1600=270, so the answer is correct\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |