document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48969>Question 48969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line in slop-intercept form of the line that is perpendicular to y= -5/3x - 2 and passes through (-3,-3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32439 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line in slop-intercept form of the line that is perpendicular to y= -5/3x - 2 and passes through (-3,-3).<BR>\n" );
document.write( "PERPENDICULAR IS GIVEN BY <BR>\n" );
document.write( "Y=3X/5+K<BR>\n" );
document.write( "IT PASSES THROUGH (-3,-3)...SO..<BR>\n" );
document.write( "-3=3*-3/5+K<BR>\n" );
document.write( "K=9/5 -3=--6/5<BR>\n" );
document.write( "Y=3X/5-6/5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );