document.write( "Question 48963: Spike averaged 45 mph driving from Rochester to Syracuse and 49 mph driving from Syracuse to Albany. If he drove a total of 237 miles in 5 hours, then how far is it from Syracuse to Albany? \n" ); document.write( "
Algebra.Com's Answer #32435 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Spike averaged 45 mph driving from Rochester to Syracuse and 49 mph driving from Syracuse to Albany. If he drove a total of 237 miles in 5 hours, then how far is it from Syracuse to Albany? \n" ); document.write( "DISTANCE FROM R TO S =X \n" ); document.write( "DISTANCE FROM S TO A =Y \n" ); document.write( "X+Y=237.........TIME TAKEN = 5 HRS \n" ); document.write( "TIME TO TRAVEL X = X/45 \n" ); document.write( "TIME TO TRAVEL Y= Y/49 \n" ); document.write( "TOTAL TIME \n" ); document.write( "X/45 + Y/49=5 \n" ); document.write( "49X+45Y=5*45*49............II \n" ); document.write( "49(237-Y)+45Y=49*225 \n" ); document.write( "4Y=49(237-225)=49*12 \n" ); document.write( "Y=49*3=147=DISTANCE FROMSYRACUSE TO ALBANY\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |