document.write( "Question 457034: 1) solve: abs(2y+4)=22-abs(6-2y)\r
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\n" ); document.write( "\n" ); document.write( "2) solve: abs(x-1)-abs(x+2)\n" ); document.write( "

Algebra.Com's Answer #324344 by lwsshak3(11628) $\"\"$ $\"About$

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1) solve: abs(2y+4)=22-abs(6-2y)
\n" ); document.write( "2) solve: abs(x-1)-abs(x+2)
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\n" ); document.write( "1)abs(2y+4)=22-abs(6-2y)
\n" ); document.write( "|2y+4|=22-|6-2y|
\n" ); document.write( "let (2y+4)<0
\n" ); document.write( "-2y-4=22-6+2y
\n" ); document.write( "-4y=22-6+4=20
\n" ); document.write( "y=-5
\n" ); document.write( "..
\n" ); document.write( "|6-2y|=22-|2y+4|
\n" ); document.write( "let (6-2y)<0
\n" ); document.write( "-6+2y=22-2y-4
\n" ); document.write( "4y=22-4+6=24
\n" ); document.write( "y=6
\n" ); document.write( "..
\n" ); document.write( "2) solve: abs(x-1)-abs(x+2
\n" ); document.write( "y=|x-1|-|x+2|
\n" ); document.write( "for x<-2
\n" ); document.write( "y=-x+1-(-x-2)
\n" ); document.write( "y=-x+1+x+2=3
\n" ); document.write( "..
\n" ); document.write( "or x>1
\n" ); document.write( "y=x-1-x-2
\n" ); document.write( "y=-3
\n" ); document.write( "..
\n" ); document.write( "for -2 ≤ x ≤1
\n" ); document.write( "y=-x+1-(x+2)
\n" ); document.write( "y=-x+1-x-2
\n" ); document.write( "y=-2x-1 \n" ); document.write( "

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