document.write( "Question 472993: Please help me find the general form of the equation of the circle
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Algebra.Com's Answer #324319 by jim_thompson5910(35256)\"\" \"About 
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Recall that the general equation of a circle is \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "So we need the center (h,k) and the radius squared \"r%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "First, let's find the center (h,k).\r
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\n" ); document.write( "\n" ); document.write( "Since the center is the midpoint of the line segment with endpoints (-6,-2) and (-4,4), we need to find the midpoint.\r
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\n" ); document.write( "\n" ); document.write( "X-Coordinate of Midpoint = \"%28x%5B1%5D%2Bx%5B2%5D%29%2F2+=+%28-6%2B-4%29%2F2=-10%2F2+=+-5\"\r
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\n" ); document.write( "\n" ); document.write( "Since the x coordinate of midpoint is \"-5\", this means that \"h=-5\"\r
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\n" ); document.write( "\n" ); document.write( "Y-Coordinate of Midpoint = \"%28y%5B1%5D%2By%5B2%5D%29%2F2+=+%28-2%2B4%29%2F2=2%2F2+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "Since the y coordinate of midpoint is \"1\", this means that \"k=1\"\r
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\n" ); document.write( "\n" ); document.write( "So the center is the point (-5, 1)\r
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\n" ); document.write( "\n" ); document.write( "Now let's find the radius squared\r
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\n" ); document.write( "\n" ); document.write( "Use the formula \"r%5E2=%28x-h%29%5E2%2B%28y-k%29%5E2\", where (h,k) is the center and (x,y) is an arbitrary point on the circle.\r
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\n" ); document.write( "\n" ); document.write( "In this case, \"h=-5\" and \"k=1\". Also, \"x=-6\" and \"y=-2\" (drawn from one of the given points -- namely the first one). Plug these values into the equation above and simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2=%28-6--5%29%5E2%2B%28-2-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2=%28-6%2B5%29%5E2%2B%28-2-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2=%28-1%29%5E2%2B%28-3%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2=1%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%5E2=10\"\r
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\n" ); document.write( "\n" ); document.write( "So because \"h=-5\", \"k=1\", and \"r%5E2=10\", this means that the equation of the circle that passes through the points (-6,-2) and (-4,4) (which are the endpoints of the diameter) is \r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%5E2%2B%28y-1%29%5E2=10\".\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"%28x%2B5%29%5E2%2B%28y-1%29%5E2=10\"
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