document.write( "Question 472969: A chemist has a 30% acid solution and a 60% solution already prepared. How
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Algebra.Com's Answer #324294 by jim_thompson5910(35256)\"\" \"About 
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Let x = amount of 30% solution, y = amount of 60% solution (both amounts in mL)\r
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\n" ); document.write( "\n" ); document.write( "Since the chemist wants 300mL, this means that \"x%2By=300\". Solve for y to get \"y=300-x\"\r
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\n" ); document.write( "\n" ); document.write( "Because \"A chemist has a 30% acid solution and a 60% solution already prepared\" and the chemist wants \"to form 300 mL of a 50% solution\", we know that \"0.3x%2B0.6y=0.5%28300%29\". Next, multiply everything by 10 to get every number to be a whole number. So \r
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\n" ); document.write( "\n" ); document.write( "\"10%280.3x%29%2B10%280.6y%29=10%2A0.5%28300%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B6y=1500\"\r
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\n" ); document.write( "\n" ); document.write( "Now plug in \"y=300-x\" and solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B6y=1500\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B6%28300-x%29=1500\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B1800-6x=1500\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x%2B1800=1500\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=1500-1800\" Subtract \"1800\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-300\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-300%29%2F%28-3%29\" Divide both sides by \"-3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=100\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now go back to \"y=300-x\" and use that to find the value of y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=300-x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=300-100\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=200\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x=100\" and \"y=200\"\r
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\n" ); document.write( "\n" ); document.write( "This means that 100 mL of 30% acid solution and 200 mL of 60% acid solution is needed to mix to get 300 mL of 50% acid solution.
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