document.write( "Question 472969: A chemist has a 30% acid solution and a 60% solution already prepared. How
\n" ); document.write( "much of each of the two solutions should be mixed to form 300 mL of a 50%
\n" ); document.write( "solution?\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance!
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Algebra.Com's Answer #324293 by stanbon(75887)\"\" \"About 
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A chemist has a 30% acid solution and a 60% solution already prepared. How
\n" ); document.write( "much of each of the two solutions should be mixed to form 300 mL of a 50%
\n" ); document.write( "solution?
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\n" ); document.write( "Using 1-variable:
\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.30x + 0.60(300-x) = 0.50*300
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "30x + 60*300 - 60x = 50*300
\n" ); document.write( "-30x = -10*300
\n" ); document.write( "x = 100mL (amt. of 30% solution needed)
\n" ); document.write( "----
\n" ); document.write( "300-x = 200mL (amt. of 60% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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