document.write( "Question 472969: A chemist has a 30% acid solution and a 60% solution already prepared. How
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document.write( "much of each of the two solutions should be mixed to form 300 mL of a 50%
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document.write( "solution?\r
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document.write( "Thank you in advance! \n" );
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Algebra.Com's Answer #324293 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A chemist has a 30% acid solution and a 60% solution already prepared. How \n" ); document.write( "much of each of the two solutions should be mixed to form 300 mL of a 50% \n" ); document.write( "solution? \n" ); document.write( "---------------------- \n" ); document.write( "Using 1-variable: \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.30x + 0.60(300-x) = 0.50*300 \n" ); document.write( "--------------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "30x + 60*300 - 60x = 50*300 \n" ); document.write( "-30x = -10*300 \n" ); document.write( "x = 100mL (amt. of 30% solution needed) \n" ); document.write( "---- \n" ); document.write( "300-x = 200mL (amt. of 60% solution needed) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |