document.write( "Question 472803: Given that x is measured in radians and x is greater than 10, find the smallest value of x such that\r
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\n" ); document.write( "\n" ); document.write( "*Please answer as soon as possible bro :)
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Algebra.Com's Answer #324221 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"10cos%28%28x%2B1%29%2F%282%29%29+=+3+\"
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document.write( "Divide both sides by 10\r\n" );
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document.write( "\"cos%28%28x%2B1%29%2F%282%29%29+=+.3+\"\r\n" );
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document.write( "Use inverse cosine on a calculator to get\r\n" );
document.write( "the principle value of 1.266103873\r\n" );
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document.write( "That's the 1st quadrant value.  There is also a\r\n" );
document.write( "4th quadrant answer of -1.266103873.  We will\r\n" );
document.write( "have to consider both cases.\r\n" );
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document.write( "FIRST QUADRANT value of \"%28x%2B1%29%2F2\"\r\n" );
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document.write( "We can add 2pn and get 1st quadrant coterminal \r\n" );
document.write( "angles with that.\r\n" );
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document.write( "So we have \r\n" );
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document.write( "\"%28x%2B1%29%2F2=1.266103873+%2B+2pi%2An\"\r\n" );
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document.write( "Solve for x:\r\n" );
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document.write( "Multiply through by 2\r\n" );
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document.write( "\"x%2B1=2.532207346+%2B+4pi%2An\"\r\n" );
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document.write( "Subtract 1 from both sides\r\n" );
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document.write( "\"x=1.532207346+%2B+4pi%2An\"\r\n" );
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document.write( "We set that greater than 10\r\n" );
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document.write( "\"1.532207346+%2B+4pi%2An%3E10\"\r\n" );
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document.write( "Solve for n:\r\n" );
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document.write( "\"4pi%2An%3E8.467792654\"\r\n" );
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document.write( "\"n%3E8.467792654%2F%284pi%29\"\r\n" );
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document.write( "\"n%3E.673845529\"\r\n" );
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document.write( "The smallest integer value of n is 1. \r\n" );
document.write( "So\r\n" );
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document.write( "\"x=1.532207346+%2B+4pi%2A1\"\r\n" );
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document.write( "x = 14.09857796\r\n" );
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document.write( "That may be the answer, but we have \r\n" );
document.write( "to consider the 4th quardrant value\r\n" );
document.write( "as well to be sure.\r\n" );
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document.write( "FOURTH QUADRANT value of \"%28x%2B1%29%2F2\"\r\n" );
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document.write( "We can add 2pn and get 4th quadrant coterminal \r\n" );
document.write( "angles with that.\r\n" );
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document.write( "So we have \r\n" );
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document.write( "\"%28x%2B1%29%2F2=-1.266103873+%2B+2pi%2An\"\r\n" );
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document.write( "Solve for x:\r\n" );
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document.write( "Multiply through by 2\r\n" );
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document.write( "\"x%2B1=-2.532207346+%2B+4pi%2An\"\r\n" );
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document.write( "Subtract 1 from both sides\r\n" );
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document.write( "\"x=-3.532207346+%2B+4pi%2An\"\r\n" );
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document.write( "We set that greater than 10\r\n" );
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document.write( "\"-3.532207346+%2B+4pi%2An%3E10\"\r\n" );
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document.write( "Solve for n:\r\n" );
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document.write( "\"4pi%2An%3E13.53220735\"\r\n" );
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document.write( "\"n%3E1.076858845\"\r\n" );
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document.write( "The smallest integer value of n that satisfies\r\n" );
document.write( "that is 2.  So\r\n" );
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document.write( "\"x=-1.532207346+%2B+4pi%2A2\"\r\n" );
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document.write( "x = 21.60053388\r\n" );
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document.write( "That is larger so the smallest solution for x\r\n" );
document.write( "that satisfies\r\n" );
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document.write( "\"10cos%28%28x%2B1%29%2F%282%29%29+=+3+\"\r\n" );
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document.write( "and is greater than 10 is 14.09857796.\r\n" );
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document.write( "Edwin

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