document.write( "Question 48953: how do i graph the equation y=3x+2 using only the slope and y-intercept and not my calculator? \n" ); document.write( "
Algebra.Com's Answer #32417 by venugopalramana(3286)\"\" \"About 
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how do i graph the equation y=3x+2 using only the slope and y-intercept and not my calculator?
\n" ); document.write( "Y INTERCEPT IS 2..SO PLOT A POINT AT 2 UNITS FROM ORIGIN ON Y AXIS SAY P.IT IS (0,2)
\n" ); document.write( "SLOPE IS 3...THAT IS (Y2-Y1)/(X2-X1)=3...SO CORRESPONDING TO INTERCEPT OF 2 UNITS ON Y AXIS,TAKE -2/3 UNITS ON X AXIS FROM ORIGIN MARKING IT AS Q (-2/3,0).
\n" ); document.write( "JOIN PQ AND EXTEND TO GET THE LINE
\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+3%2Ax%2B2%29+\"
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